|
Question 7917: the larger of two consecutive integers is 10 more that twice the smaller. what are the integers?
Answer by prince_abubu(198)   (Show Source):
You can put this solution on YOUR website! Alright. The first thing they said is that there are two consecutive integers. This means that if you pick out any integer S, you'd have to choose the integer after (or before) S, which would be S + 1. We're gonna choose S + 1 because the problem says something about the larger integer. So, we'll let S be the integer we choose, and S + 1 be the larger integer.
They said that the larger integer, the (S + 1) is 10 more than twice the smaller. Twice the smaller would be 2S, and "10 more than twice the smaller" would mean that you'd add the 10 to the 2S to equal the S + 1. So far, we have the equation:
 <---- start here.
 <--- subtract S from both sides
 <---- the smaller integer turned out to be -9. If S = -9, the S + 1 = -8.
That seems weird! Let's see The larger, -8, is 10 more than twice -9? Let's see. -8 ?= 2*-9 + 10 ---> -8 ?= -18 + 10. Yes.
|
|
|
| |
