SOLUTION: seven consecutive natural numbers have a sum equal to 105. how many are divisible by 5

Question 785849: seven consecutive natural numbers have a sum equal to 105. how many are divisible by 5

Found 2 solutions by vic21, Alan3354:
Answer by vic21(4) (Show Source): You can put this solution on YOUR website!
1x+2x+3x+4x+5x+6x+7x=105
28x=105
x= 3.75
1(3.75)= 3.75
2(3.75)= 7.5
3(3.75)= 11.25
4(3.75)=15 ( only number divisible by 5)
5(3.75)=18.75
6((3.75)=22.5
7((3.75)=26.25
answer only 1 is divisible by 5
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
seven consecutive natural numbers have a sum equal to 105. how many are divisible by 5
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105/7 = 15, the middle number
--> 12, 13, 14, 15, 16, 17, 18
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Only 15 is evenly divisible by 5.

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