SOLUTION: The product of two consecutive integers is 71 more than the square of the preceding smaller integer. Find the numbers.

Question 778871: The product of two consecutive integers is 71 more than the square of the preceding smaller integer. Find the numbers.
Answer by ramkikk66(644) (Show Source): You can put this solution on YOUR website!

The product of two consecutive integers is 71 more than the square of the preceding smaller integer. Find the numbers.
Ans:
Let the integers be n and n+1. Then the preceding smaller integer is (n-1).
It is given that


Cancelling out n^2 and simplifying


The numbers are 24 and 25.
Hope you got it :)

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