SOLUTION: Number problem.
If one-half of one integer is subtracted from three-fifths of the
next consecutive integer, the difference is 3. What are the two integers?
thanks
Algebra.Com
Question 77846: Number problem.
If one-half of one integer is subtracted from three-fifths of the
next consecutive integer, the difference is 3. What are the two integers?
thanks
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let x=one integer
Then x+1=next consecutive integer
Now here's what we are told:
(3/5)(x+1)-(1/2)x=3 multiply each term by 10 to get rid of the fractions
(3/5)(10)(x+1)-(1/2)(10)(x)=3(10) simplify
6(x+1)-5x=30 get rid of parens
6x+6-5x=30 subtract 6 from both sides
6x+6-6-5x=30-6 collect like terms
x=24-------------------------------one integer
x+1=24+1=25----------------------- next consecutive integer
ck
(1/2) of one integer =(1/2)24=12
(3/5) of the next consecutive integer =(3/5)(25)=15
If you subtract the two, the difference is 3
So 15-12=3
3=3
Hope this helps-----ptaylor
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