SOLUTION: Find two consecutive odd integers so that the square of the larger exceeds their product by 34.

SOLUTION: Find two consecutive odd integers so that the square of the larger exceeds their product by 34.

Algebra.Com

Question 771887: Find two consecutive odd integers so that the square of the larger exceeds their product by 34.
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
Let n and n+2 the odd consecutive integers
Then:
(n+2)^2 = n(n+2)+34
n^2+4n+4 = n^2+2n+34
4n+4 = 2n+34
2n+4 = 34
2n = 30
n = 15
Answer: 15 and 17
I can help you with more questions at: mthman@gmail.com
Thanks
RELATED QUESTIONS
Find two consecutive odd integers so that the square of the larger exceeds their product... (answered by htmentor,Alan3354)

Find two consecutive odd integers so that the square of the larger exceeds their... (answered by josgarithmetic,JBnovelwriter)

The square of the smaller of two consecutive odd integers exceeds their sum by 97. Find... (answered by solve_for_x)

find three consecutive positive odd integers such that the product of the two smaller... (answered by Alan3354)

Find the three consecutive odd integers such that the sum of the two SMALLER odd integers (answered by josgarithmetic)

find two consecutive odd integers such that three times the smaller one exceeds two times (answered by tommyt3rd,MathTherapy)

Find two consecutive odd integers such that three times the smaller one exceeds two times (answered by CubeyThePenguin)

find two consecutive odd integers such that three times the smaller exceeds tow time the... (answered by JulietG)

Find three consecutive odd integers such that the sum of the first two odd integers... (answered by MathLover1)