SOLUTION: Find two consecutive odd integers such that 67 more than the lesser is six times the greater.
The lesser consecutive off integer is __, and the greater consecutive odd integer is
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Question 768664: Find two consecutive odd integers such that 67 more than the lesser is six times the greater.
The lesser consecutive off integer is __, and the greater consecutive odd integer is __.
Answer by tommyt3rd(5050) (Show Source): You can put this solution on YOUR website!
n+67 = 6(n+2)
5n=67-12
n=11
they are 11 and 13
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