SOLUTION: please help me to solve this problem:
(divide the number in three parts such that the second part is twice the first and the third part is 7 less than the second.)
Algebra.Com
Question 768338: please help me to solve this problem:
(divide the number in three parts such that the second part is twice the first and the third part is 7 less than the second.)
Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!
parts x, y, z.
The number, Q=x+y+z
Question is: Find Q.
and this is a far as can be found. You need more information to go any more.
RELATED QUESTIONS
Divide 98 into three parts such that the second part is twice the first, and the third... (answered by rothauserc)
Divide 180 in two parts such that the first part is 12 less than twice the second... (answered by jorel555)
Divide 178 in two parts such that the first is 8 lees than twice the second part. (answered by solver91311)
Please help me how to solve this.....Divide 60 into 2 parts such that twice the smaller... (answered by solver91311)
Divide 150 into three parts such that the second part is five-sixth of the first and the... (answered by josgarithmetic)
divide 105 into two parts such that one half of the first exceeds one fifth of the second (answered by richwmiller)
divide 2790 into two parts such that 8% of the first part is equal to 10%of the second... (answered by lwsshak3)
please help me solve this word problem, Find three consecutive integers such that twice... (answered by stanbon)
separate the number 78 into three parts so that the second part is twice the first part... (answered by stanbon,Earlsdon)