SOLUTION: the sum of two numbers is 47 one of the numbers is 2 more than twice the other number find the value of the smaller number?
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Question 767153: the sum of two numbers is 47 one of the numbers is 2 more than twice the other number find the value of the smaller number?
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
x = one number
2x + 2 = other number {one number is two more than twice the other}
x + 2x + 2 = 47 {the sum of the two numbers is 47}
3x + 2 = 47 {combined like terms}
3x = 45 {subtracted 2 from each side}
x = 15 {divided each side by 3}
2x + 2 = 32 {substituted 15, in for x, into 2x + 2}
15 is the smaller number
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