SOLUTION: The sum of three numbers is 62 . The first number is 10 more than the second . The third number is 2 times the first. What are the numbers?

Question 766646: The sum of three numbers is 62 . The first number is 10 more than the second . The third number is 2 times the first. What are the numbers?
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
x = the second number
x + 10 = the first number
2(x + 10) = the third number

x + x + 10 + 2(x + 10) = 62 {sum of the three numbers is 62}
x + x + 10 + 2x + 20 = 62 {used distributive property}
4x + 30 = 62 {combined like terms}
4x = 32 {subtracted 30 from each side}
x = 8 {divided each side by 4}
x + 10 = 18 {substituted 8, in for x, into x + 10}
2(x + 10) = 36 {substituted 8, in for x, into 2(x + 10)}

first number is 18
second number is 8
third number is 36

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