SOLUTION: 42 is divided into two parts such that five times the second part exceeds four time the first part by 48.find the first part and second part respectively.

Question 765853: 42 is divided into two parts such that five times the second part exceeds four time the first part by 48.find the first part and second part respectively.
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Two parts, m and n.

, "five times the second part exceeds four time the first part by 48."
Five times the second part is 5n.
Four times the first part is 4m.
Exceeding 4m by 48 is 4m+48.

The choice is yours how to solve the two equations for m and n. Maybe try m=42-n and substitute; and simplify to solve first for n...
.
.

therefore
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