SOLUTION: Please help me!
Here is the question--
A number of two digits is less than four times the product of its digits by 5, and the digit in the ten's place exceeds the digit in the un
Algebra.Com
Question 758948: Please help me!
Here is the question--
A number of two digits is less than four times the product of its digits by 5, and the digit in the ten's place exceeds the digit in the unit's place by one. Find the number.
I know that the number is 10x + y but i cannot get the equation to work out 'x' and 'y'.
Thank You for your time and help :D
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The number itself, is, as you state: 
IF you let 
represent the 10s digit and 
represent the 1s digit.
Then the product of the digits is 
and "less than 4 times the product of its digits by 5" is 
, leaving us:
But then we are also given that the 10s digit is 1 more than the 1s digit, in other words: 
. So then, by substitution:
\ +\ y\ =\ 4(y\ +\ 1)y\ =\ 5)
Solve for , then calculate 
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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