SOLUTION: What number exceeds 23 by 4 more than twice the amount by which 15 exceeds -3?

Question 75160: What number exceeds 23 by 4 more than twice the amount by which 15 exceeds -3?
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let x=the number that exceeds 23
Then x-23=the amount that the number exceeds 23
Now we know that 15 exceeds -3 by 18 (15-(-3)=18) and 4 more than twice this amount is 2*18+4=40. So our equation to solve is:
x-23=40 add 23 to both sides
x=63 ------------------------the number
CK
x-23=2*18+4
63-23=36+4
40=40

Hope this helps-------------ptaylor

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