SOLUTION: There are three consecutive integers. If the square of the last plus the product of the other two is 137, find the sum of the integers. If the numbers were three rational number, h

Question 742320: There are three consecutive integers. If the square of the last plus the product of the other two is 137, find the sum of the integers. If the numbers were three rational number, how would this affect the result?
Answer by mananth(16949) (Show Source): You can put this solution on YOUR website!
let the integers be (a-1),a, a+1
a(a-1)+(a+1)^2=137
a^2-a+a^2+2a+1=137
2a^2+a-136=0

2a^2+17a-16a-136=0
2a(a+8.5)-16(a+8.5)=0
(2a-16)(a+8.5)=0
2a=16 a=8
7,8,9
24 is the sum

OR a=-8.5
not an integer so ignore
RELATED QUESTIONS
Find three consecutive integers such that the square of the first plus the product of the (answered by Alan3354)

Find three consecutive integers such that the square of the first plus the product of... (answered by josgarithmetic)

The sum of two consecutive integers is �137. Find the least of the two integers. (answered by Fombitz)

The sum of two consecutive integers is �137. Find the least of the two... (answered by Fombitz)

Three consecutive positive integers such that the sum of the square of the first and the... (answered by mananth)

Find three consecutive odd integers such that the square of the third integer plus the... (answered by Alan3354)

The sum of two consecutive odd integers is 137. Find the... (answered by KMST)

find three consecutive integers such that the product of the first two plus the product... (answered by math_helper,ankor@dixie-net.com,MathTherapy)

there are three consecutive integers. the product of the first two plus the third integer (answered by KMST)