SOLUTION: the average of six consecutive in integers in increasing order of size is 9.5. what is he average of the last 3 integers?

SOLUTION: the average of six consecutive in integers in increasing order of size is 9.5. what is he average of the last 3 integers?

Algebra.Com

Question 738203: the average of six consecutive in integers in increasing order of size is 9.5. what is he average of the last 3 integers?
Answer by mananth(16949) (Show Source): You can put this solution on YOUR website!
let the numbers be x,x+1,x+2,x+3,x+4,x+5
Total = 6x+15
numbers = 6
average = 9.5 = (6x+15)/6
multiply by 6
57=6x+15
-15
42=6x
/6
x=7
the numbers are 7,8,9,10,11,12
10+11+12=33
33/3=11
average of last three numbers is 11
RELATED QUESTIONS
Hi the mean of 14 consecutive integers is 27.5.if the integers are in increasing order (answered by Boreal)

Twelve consecutive integers are arranged in order from least to greatest. If the sum of... (answered by chessace,bucky)

The average of 6 consecutive integers is 37/2 . What is the average of the first 5 of... (answered by Alan3354)

If the average of ten consecutive odd integers is 20, what is the average of the last... (answered by RAY100,Targetweek)

the average of three consecutive numbers is 9 what are the the... (answered by Alan3354,DrBeeee)

The average of 5 consecutive integers is 50. Find the... (answered by Alan3354)

The average of seven consecutive integers is 10. What are the seven integers? (answered by Alan3354)

The average of 16 consecutive positive integers is 30.5what is the average of the first 8 (answered by ikleyn,greenestamps)

Ten consecutive integers are arranged in order from least to greatest. If the sum of the... (answered by checkley77)