SOLUTION: find two numbers whose sum is 12 and whose difference between their squares is 48.
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Question 73655: find two numbers whose sum is 12 and whose difference between their squares is 48.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let the two numbers be a and b. From the problem description, you can write:
1) and
2)
Rewrite equation 1) as: a = 12-b and substitute for the a in equation 2).
2a) Simplify and solve for b.
Add 24b to both sides.
Subtract 48 from both sides.
Divide both sides by 24.
and...
The two numbers are 4 and 8
Check:
= 12 Their sum is 12.
The difference of their squares is 48.
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