SOLUTION: the product of two consecutive odd integers is 1 less than 4 times their sum. find the two integers. hint there will be two sets of solutions.

Question 736140:
the product of two consecutive odd integers is 1 less than 4 times their sum. find the two integers. hint there will be two sets of solutions.
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
LET X & (X+2) BE THE 2 ODD INTEGERS.
X(X+2)=4(X+X+2)-1
X^2+2X=4(2X+2)-1
X^2+2X=8X+8-1
X^2+2X-8X-7=0
X^2-6X-7=0
(X-7)(X+1=0
X-7=0
X=7 ANS.
7+2=9 ANS.
PROOF:
7*9=4(7+9)-1
63=4*16-1
63=64-1
63=63
X+1=0
X=-1 ANS.
-1+2=1 ANS.
PROOF:
-1*+1=4(-1+1)-1
-1=4*0-1
-1=-1
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