SOLUTION: If n is the first of two consecutive even integers, write an equation that can be used to find the integers if the sum of the squares of twice the first and the second is 100.

Algebra.Com
Question 733158: If n is the first of two consecutive even integers, write an equation that can be used to find the integers if the sum of the squares of twice the first and the second is 100.
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
If n is the first of two consecutive even integers,
write an equation that can be used to find the integers
if the sum of the squares of twice the first and the second is 100.
:
let n and (n+2) = the two even consecutive integers
:
the sum of the squares of twice the first and the second is 1
(2x)^2 + (x+2)^2 = 100
4x^2 + x^2 + 4x + 4 = 100
5x^2 + 4x + 4 - 100 = 0
5x^2 + 4x - 96 = 0
Factors to
(5x+24)(x-4) = 0
the integer solution
x = 4
:
The two consecutive even integers: 4, 6
:
:
Check 8^2 + 6^2 = 100

RELATED QUESTIONS

The sum of 3 consecutive even integers is 552. Write an equation that can be used to find (answered by solver91311)
The sum of two consecutive integers is 143. Write an equation that can be used to find... (answered by josmiceli)
The sum of two consecutive even integers is 198.If the n represents the smaller of these... (answered by lynnlo)
the sum of two consecutive integers is 153. which equation can be used to find the first... (answered by stanbon,AnlytcPhil)
write and solve an equation to solve each problem 3 consecutive even integers can be... (answered by ankor@dixie-net.com,Alan3354)
The sum of the reciprocals of two consecutive even integers us 11/60. Write an equation... (answered by stanbon)
Write an equation that can be used to solve the problem. Then answer the question asked.... (answered by mananth)
the product of two consecutive even integers is 14 more than their sum. set up an... (answered by Alan3354)
The sum of the reciprocals of two consecutive positive integers is seventeen seventy-two. (answered by nshah11)