SOLUTION: Separate the number 50 into three parts so that the second number is twice the first number, and the third number is 5 more than the second number.

SOLUTION: Separate the number 50 into three parts so that the second number is twice the first number, and the third number is 5 more than the second number.

Algebra.Com

Question 723233:
Separate the number 50 into three parts so that the second number is twice the first number, and the third number is 5 more than the second number.
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
F+S+T=50
S=2F
T=S+5
F+2F+2F+5=50
5F=50-5
5F=45
F=45/5
F=9 ANS FOR THE FIRST NUMBER.
S=2*9=18 ANS. FOR THE SECOND NUMBER.
T=18+5=23 ANS. FOR THE THIRD NUMBER.
PROOF:
9+18+23=50
50=50
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