SOLUTION: find two positive consecutive multiples of 3 such that the sum of their square is 369
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Question 708813: find two positive consecutive multiples of 3 such that the sum of their square is 369
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let
represent a postive multiple of 3. Then
is the next consecutive positive multiple of 3. The sum of their squares is:
Expand the squared binomial, collect like terms, put the quadratic into standard form, and solve. Hint: this quadratic is factorable. Discard the negative root. Verify that the positive root is, indeed, divisible by 3. Then calculate
John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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