SOLUTION: find three consecutive even integers such that fives times the middle integer is twelve more then twice the sum of the first and third.

Question 708120: find three consecutive even integers such that fives times the middle integer is twelve more then twice the sum of the first and third.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
n is an integer.

fives times the middle integer is:
5(2n+2)=

twelve more then twice the sum of the first and third.:
12+2(2n+2n+4)

Putting it together:
5(2n+2)=12+2(2n+2n+4)
10n+10=12+8n+8
10n+10=8n+20
2n+10=20
2n=10, n=5.

The numbers are 10, 12, 14.

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