SOLUTION: one number is 7 less than the second number. twice the second number is 7 less than 5 times the first. find the smaller of the two.

Question 707091: one number is 7 less than the second number. twice the second number is 7 less than 5 times the first. find the smaller of the two.
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
a is first number; b is second number.

one number is 7 less than the second number.
twice the second number is 7 less than 5 times the first.
find the smaller of the two.

Those two equations turn into system:

Multiply first equation by 2 and subtract from the second equation.

5a-2b-(2a-2b)=7-(-14)
3a+0=+7
, same as

Use a to find b. Using original first equation, a=-7+b, b=a+7,
b=7/3+7=
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