SOLUTION:
3) The sum of twice an integer and three times its square is 261. Find the integer.
The answer is 9 & 4 (I think) BUT. what is the work to get it? please help.
Algebra.Com
Question 702917:
3) The sum of twice an integer and three times its square is 261. Find the integer.
The answer is 9 & 4 (I think) BUT. what is the work to get it? please help.
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
2X+3X^2=261
3X^2+2X-261=0
(3X+29)(X-9)=0
X-9=0
X=9 ANS.
PROOF:
2*9+3*9^2=261
18+3*81=216
18+243=261
261=261
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