SOLUTION: the sum of four consecutive integers is 2 more than five times the first integer.

Algebra.Com
Question 701427: the sum of four consecutive integers is 2 more than five times the first integer.
Answer by shanehhhh47(5)   (Show Source): You can put this solution on YOUR website!
First represent your values:
let x be the 1st integer
x+1 be the 2nd integer
x+2 be the 3rd integer
x+4 be the 4th integer
Then equate according to the given conditions:
x+x+1+x+2+x+3+x+4=2+5x
Combine Similar terms:
4x+6=2+5x
x=4
Therefore the integers are 4,5,6 and 7. :)

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