The other tutor's answer is incorrect. The first 101 integers consist of 50 even numbers and 51 odd numbers sum of odds = 1 + 3 + 5 + 7 + ··· + 95 + 97 + 99 + 101 sum of evens = 2 + 4 + 6 + ··· + 94 + 96 + 98 + 100 ------------------------------------------------------- difference = 1 + 1 + 1 + 1 + ··· + 1 + 1 + 1 + 1 When we subtracted them above, term by term, there is a 1 in each of the positions of the 51 odd numbers. The sum of 51 1's is 51. Answer: 51 Edwin