SOLUTION: Please solve the following question: The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle.

Question 70103: Please solve the following question:
The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle.
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Let the width be "x".
Then length = "2x+8"
Perimeter = 2(length + width)
64 = 2(2x+8+x)
32=3x+8
3x=24
x=8 in. (this is the width)
Cheers,
Stan H
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