SOLUTION: find three consecutive natural numbers such that five times the first is 24 more than the sum of the other two

SOLUTION: find three consecutive natural numbers such that five times the first is 24 more than the sum of the other two

Algebra.Com

Question 701004:
find three consecutive natural numbers such that five times the first is 24 more than the sum of the other two
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
LET X, X+1 & X+2 BE THE 3 NUMBERS.
5X=(X+1)+(X+2)+24
5X=2X+3+24
5X-2X=27
3X=27
X=27/3
X=9 ANS. FOR THE FIRST NUMBER.
9+1=10 ANS. FOR THE SECOND NUMBER.
9+2=11 ANS. FOR THE THIRD NUMBER.
PROOF:
5*9=10+11+24
45=45
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