SOLUTION: Find two integers which differ by 8 such that their product is-15.

Question 697467: Find two integers which differ by 8 such that their product is-15.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
two integers differ by 8: x-y = 8

solve for y: y = x-8

their product is -15: xy = -15

plug in y = x-8: x(x-8) = -15

Now solve for x

x(x-8) = -15

x^2 - 8x = -15

x^2 - 8x + 15 = 0

Use the quadratic formula to solve for x

Plug in , ,

or

or

or

or

Now that you know x = 5, you can use this to find that y = -3

Or if x = 3, then you can find out that y = -5. Both of these y values are found when you plug in the corresponding x value into and you solve for y.

So the two numbers are 5 and -3. Also, another pair of numbers is 3 and -5
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