SOLUTION: find two consecative odd number such that one fifth of the smaller exceeds one ninth of the greater by 2

Question 696896: find two consecative odd number such that one fifth of the smaller exceeds one ninth of the greater by 2
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find two consecutive odd numbers such that one fifth of the smaller exceeds one ninth of the greater by 2
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1st: 2x-1
2nd: 2x+1
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Equation:
(1/5)(2x-1) = (1/9)(2x+1) + 2
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Multiply thru by 45 to get:
9(2x-1) = 5(2x+1) + 90
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18x - 9 = 10x + 95
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8x = 104
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x = 13
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1st: 2x-1 = 25
2nd: 2x+1 = 27
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Cheers,
Stan H.
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