SOLUTION: A group of friends are travelling to the high school basketball game. They will need to take two cars. The first car leaves right away at 6:15PM and travels at 42 miles per hour. T

Question 696235: A group of friends are travelling to the high school basketball game. They will need to take two cars. The first car leaves right away at 6:15PM and travels at 42 miles per hour. The second car has to wait 30 minutes for Sally, and when they leave they travel at an average rate of 81.14 km per hour. They reach the school at the exact same time, what time is that?
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
D=RT
D=42T FOR THE FIRST CAR.
D=81.14(T-.5) FOR THE SECOND CAR.
THE 2 DISTANCES ARE THE SAME.
42T=81.14(T-.5)
42T=81.14T-40.57
42T-81.14T=-40.57
-39.14T=-40.57
T=-40.57/-39.14
T=1.037 HOUR ANS.
PROOF:
42*1.037=81.14(1.037-.5)
43.53=81.14*.537
43.55=43.57

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