SOLUTION: find three consecutive integers such that the first added to 5 times the second exceeds 3 times the last by 51.

Question 694690: find three consecutive integers such that the first added to 5 times the second exceeds 3 times the last by 51.
Answer by 55305(86) (Show Source): You can put this solution on YOUR website!
First lets assume the three number are n-1,n,and n+1, since the numbers are consecutive integers. Our equation would be
, which simplifies to
. Now we can solve by subtracting 3n and adding 1 to each side:

that would mean that n is not an integer, and there are no consecutive integers which have those properties.
Numbers that work out that differ by 1 are

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