SOLUTION: find three consecutive numbers such that 3 times the first is equal to 8 more than the sum of the other two.

Question 681956: find three consecutive numbers such that 3 times the first is equal to 8 more than the sum of the other two.
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
x x+1 x+2
...
3x = x+1+x+2+8
3x = 2x + 11
3x - 2x = 11
x = 11
...
The numbers are
11, 12 and 13
.....................
Have more questions?
Email: HomeworkHelpers@readingboosters.com
Delighted to help.
-Reading Boosters
Website: www.MyHomeworkAnswers.com
Wanting for others what we want for ourselves.

RELATED QUESTIONS
Find three consecutive numbers such that three times the first number is equal to the sum (answered by solve_for_x)

i need help solving this problem. find 3 consecutive numbers such that 4 times the... (answered by ewatrrr)

find 3 cinsecutive numbers such that 4 times the first is equal to 7 more than the sum of (answered by JimboP1977)

find three consecutive natural numbers such that five times the first is 24 more than (answered by checkley79)

Find 3 consecutive numbers such that 4 times the first is equal to 7 more than the sum of (answered by ankor@dixie-net.com)

There lot of questions: 1. find four consecutive odd numbers such that four times the... (answered by nyc_function)

Find three consecutive integers such that the sum of the three is equal to 2 times more... (answered by cornelius.bayler)

Three consecutive odd integers such that the sum of the first two is equal to eleven... (answered by CubeyThePenguin)