SOLUTION: the sum of two numbers is 48 the first is 8 less than the second. find the numbers

Algebra.Com
Question 681297: the sum of two numbers is 48 the first is 8 less than the second. find the numbers
Answer by poweezo(4)   (Show Source): You can put this solution on YOUR website!
x(x-8)=48
x^2-8x=48
x^2-8x-48=0
(x-12)(x+4)=0
x-12=0 or x+4=0
x=12 or x=-4
The first number is 4 and the second is 12

RELATED QUESTIONS

The difference of two numbers (the second minus the first) is 48. The second is 8 less... (answered by jim_thompson5910)
the second of two numbers is 3 less than twice the first. their sum is 18. find the two... (answered by rfer)
the sum of two numbers is 45. the first is 9 less than the second find the... (answered by oberobic,subudear)
The sum of two numbers is 75. The second number is 3 less than twice the first. Find the... (answered by amoresroy)
the sum of two numbers is 75. the second number is 3 less than twice the first. find the... (answered by powercenter)
The sum of two numbers is 50. The first is 5 less than 4 times the second. Find the... (answered by Fombitz)
The difference of two numbers is 48. The second is 8 less than 5 times the first. What... (answered by wgunther)
The second of two numbers is 3 less than twice th first . Their sum is 42. Find the... (answered by nyc_function)
The sum of two numbers is negative 8 the first number is 22 less than the second number,... (answered by edjones)