SOLUTION: find four consecutive odd integers such that twice the sum of the first two is 56 greater than the sum of the third and the fourth. plesae show detail thank you!

Question 672800: find four consecutive odd integers such that twice the sum of the first two is 56 greater than the sum of the third and the fourth.
plesae show detail thank you!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find four consecutive odd integers such that twice the sum of the first two is 56 greater than the sum of the third and the fourth.
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1st: 2x-3
2nd: 2x-1
3rd: 2x+1
4th: 2x+3
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Equation:
2(4x-4) = (4x+4)+56
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8x-8 = 4x + 60
4x = 68
x = 17
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1st: 2x-3 = 31
2nd: 33
3rd: 35
4th: 37
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Cheers,
Stan H.
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