SOLUTION: the product of two integers is 80. one number is 8 more than 3 times the other number. find the number.
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Question 670541: the product of two integers is 80. one number is 8 more than 3 times the other number. find the number.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let the integers be x & y
xy=80
OR
x=80/y
x=3y+8
3y+8= 80/y
multiply equation by y
3y^2+8y=80
3y^2+8y-80=0
a= 3 b= 8 c= -80
b^2-4ac= 64 - -960
b^2-4ac= 1024
= 32
)/
y1=( -8 + 32 )/ 6
y1= 4
y2=( -8 - 32 )/ 6
y2= -6.67
Ignore negative value it is not an integer
y = 4
The integers are 4 & 20
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