SOLUTION: Of two consecutive integers, four times the lesser exceeds the three times the greater by 30. What are the integers?

Question 668666: Of two consecutive integers, four times the lesser exceeds the three times the greater by 30. What are the integers?

Answer by amazingrace333(11) (Show Source): You can put this solution on YOUR website!
Solve by representing the two consecutive integers as x, and x+1
Four times the lesser would be 4x.
Three times the greater would be 3(x+1).
Now what else do you know to solve this?...that 4x is 30 more than 3(x+1) or in equation format:
4x = 30 + 3(x+1)
Now simplify and solve as follows:
4x = 30 + 3x +3
4x = 33 + 3x
4x - 3x = 33 + (3x - 3x)
x = 33
Check your answer:
4x = 4(33) = 132
x+1 = 34
3(34) = 102
132 - 102 = 30
So the correct integers are 33 and 34.
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