SOLUTION: This is my question. The product of two consecutive even integers is 56. Find the two integers. I got this far x(x+2)= 56 x^+2x= 56 x^+2x-56 = 0 (x-?)(x+?)= 0 thanks

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Question 6677: This is my question.
The product of two consecutive even integers is 56. Find the two integers.
I got this far
x(x+2)= 56
x^+2x= 56
x^+2x-56 = 0
(x-?)(x+?)= 0
thanks
Found 2 solutions by xcentaur, ichudov:
Answer by xcentaur(357)   (Show Source): You can put this solution on YOUR website!
good work on getting this far,
x^+2x-56 = 0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=228 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 6.54983443527075, -8.54983443527075. Here's your graph:
Answer by ichudov(507)   (Show Source): You can put this solution on YOUR website!
great job so far. now you have to solve the quadratic equation
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=228 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 6.54983443527075, -8.54983443527075. Here's your graph:


the answer to this equation is not integer.
so, the answer is that there is no answer to your problem. It is a trick problem.
Think about it, product of consecutive integers 6 and 8 is 48, and for the next two consecutive integers (8 and 10) it is 80.
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