SOLUTION: Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46.

Question 66701: Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46.

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Try this!
Let n be the first integer, then n+1 is the next consecutive integer. From the problem description, you can write:
Simplify and solve for n.
Combine like-terms.
Subtract 4 from each side.
Divide both sides by 6.
This is the first integer.
This is the next consecutive integer.
Check:
2(7) + 4(8) = 14 + 32 = 46 OK!

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