SOLUTION: Find 3 consecutive even numbers such that the sum of twice the first number and the third number is 30 more than the second number

Algebra.Com
Question 666113: Find 3 consecutive even numbers such that the sum of twice the first number and the third number is 30 more than the second number
Answer by swincher4391(1107)   (Show Source): You can put this solution on YOUR website!
Let x be the first number.
Similarly, x+2 and x+4 are the next consecutive even numbers.
Sum of twice the first number and the third number is 30 more than the second would be:
2(x) + x+4 = x+2 + 30

2x + x + 4 = x + 32
3x + 4 = x + 32
2x = 28
x = 14
So, the numbers are 14,16,18.

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