SOLUTION: hi thank you for your help i was wondering if you could show me how to do a problem that is... there are four consecutive integers three times the greatest is 6 more than the sum

Question 662587: hi thank you for your help
i was wondering if you could show me how to do a problem that is...
there are four consecutive integers three times the greatest is 6 more than the sum of the other three??
thank you very much for taking your time to help me i would really appreciate it if you took a look at this question thanks!
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
x x+1 x+2 x+3
3(x+3) = 6+(x+x+1+x+2)
3x + 9 = 6 + 3x + 3
3x + 9 = 3x + 9
3x+9 such that x = 3
Integers are 3, 4, 5 and 6
Proof
3(6) = 18
6 + (3+4+5) = 6 + 12 = 18
.................
Delighted to help.
-Reading Boosters
What we want for others what we want for ourselves.
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