SOLUTION: victor has 16.25 in coin if there were twice as many 5 centavo coins as 25 centavo coin and as many 10 centavo coin as 5 centavo coin and 25 centavo coin combine how many coin of e

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Question 662421: victor has 16.25 in coin if there were twice as many 5 centavo coins as 25 centavo coin and as many 10 centavo coin as 5 centavo coin and 25 centavo coin combine how many coin of each type were there?
Answer by raymond123456(4)   (Show Source): You can put this solution on YOUR website!
Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: x=2.
  • Graphical form: Equation was fully solved.
  • Text form: x+x-x+2x=6 simplifies to 0=0
  • Cartoon (animation) form:
    For tutors: simplify_cartoon( x+x-x+2x=6 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at .
Eliminated similar terms highlight_red%28+x+%29,highlight_red%28+x+%29,highlight_red%28+-x+%29,highlight_red%28+2%2Ax+%29 replacing them with highlight_green%28+%281%2B1-1%2B2%29%2Ax+%29
It becomes .
Look at .
Added fractions or integers together
It becomes .
Look at .
Remove unneeded parentheses around factor highlight_red%28+3+%29
It becomes .
Look at .
Moved these terms to the left highlight_green%28+-6+%29
It becomes .
Look at .
Solved linear equation highlight_red%28+3%2Ax-6=0+%29 equivalent to 3*x-6 =0
It becomes .
Result:
This is an equation! Solutions: x=2.

Universal Simplifier and Solver


Done!
Solved by pluggable solver: Linear System solver (using determinant)
Solve:


Any system of equations:


has solution

or



(x=1, y=1}
Solved by pluggable solver: SOLVE a linear equation
Solve . Move 1 to the right: . Divide by 2:
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=16 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 3, -1. Here's your graph:
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