SOLUTION: Find three consecutive negative integers such that 3 times the product of the first and third exceeds twice the product of the first and second by 32.

Question 65447This question is from textbook An Incremental Development
: Find three consecutive negative integers such that 3 times the product of the first and third exceeds twice the product of the first and second by 32. This question is from textbook An Incremental Development

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find three consecutive negative integers such that 3 times the product of the first and third exceeds twice the product of the first and second by 32.
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Let the integers be x, x+1, x+2
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3x(x+2)-32=2x(x+1)
3x^2+6x-32 = 2x^2+2x
x^2+4x-32=0
(x+8)(x-4)=0
x=-8
x+1=-7
x+2=-6
Cheers,
Stan H.
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