SOLUTION: Find a number such that twice the number increased by seven is the same as four times the number decreased by three.
Algebra.Com
Question 648211: Find a number such that twice the number increased by seven is the same as four times the number decreased by three.
Answer by shweta(56) (Show Source): You can put this solution on YOUR website!
Let the required number be 'x'
Required equation:
2(x+7)=4(x-3)
2x+ 14=4x-12
2x-4x= -12-14
-2x=-26 ( minus sign get cancelled with each other)
2x=26
x=26/2
x=13
Required number is 13
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