SOLUTION: please help me this problem....find four consecutive odd integers whose sum is 416.

Question 635135: please help me this problem....find four consecutive odd integers whose sum is 416.
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
Let X, X+2, X+4, X+6 be the 4 integers.
4X+12=416
X+(X+2)+(X+4)+(X+6)=416
4X+12=416
4X=416-12
4X=404
X=404/4
X=101 ANS. FOR THE FIRST INTEGER.
101+2=103 ANS. FOR THE SECOND INTEGER.
101+4=105 ANS. FOR THE THIRD INTEGER.
101+6=107 ANS. FOR THE FOURTH INTEGER.
PROOF:
101+103+105+107+=416
416=416
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