SOLUTION: Find two consecutive even integers whose product is 72. Find two consecutive even integers whose product is 168.

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Question 632114: Find two consecutive even integers whose product is 72.

Find two consecutive even integers whose product is 168.

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Find two consecutive integers, whose product is 72.
x(x+1) = 72
x^2 + x - 72 = 0
(x+9)(x-8) = 0 , x = -9 or x = 8
two consecutive integers are: -9, -8 or 8, 9
There are no two consecutive even integers whose product is 72
Find two consecutive even integers , whose product is 168.
x(x+2) = 168
x^2 + 2x - 168 = 0
(x+14)(x-12) = 0. x = -14 or x = 12
two consecutive even integers are: -14, -12 or 12, 14
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