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put this solution on YOUR website!A golf ball is hit into the air, and its height h in feet after t seconds is given by h(t) = -16t^2 + 128t.
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a) what is the height of the golf ball when it is hit?
When the ball is hit, time, t = 0
h(t) = -16(0^2) + 128(0)
h(t) = 0 ft high when t=0
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b) After how many seconds does the golf ball reach its maximum height?
Max height occurs at the axis of symmetry
Find the axis of symmetry of h = -16t^2+128t using the formula x = -b/(2a)
a=-16, b=128
t =
t =
t = 4 seconds to reach max height
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c) Determine the maximum height of the golf ball?
Replace t with 4, find h(t)
h(t) = -16(4^2) + 128(4)
h(t) = -16*16 + 512
h(t) = -256 + 512
h(t) = 256 ft is the max height
:
Graphically, time on the x axis, height on the y axis
