# SOLUTION: find two consecutive positive integers such that the square of the smaller integer added to six times the larger integer is equal to 61

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 Question 625429: find two consecutive positive integers such that the square of the smaller integer added to six times the larger integer is equal to 61Answer by oscargut(900)   (Show Source): You can put this solution on YOUR website!Those integers are n and n+1 where n^2+6(n+1)=61 n^2+6n-55 = 0 (n+11)(n-5) = 0 n = -11 or n = 5 Then n = 5 and n+1 = 6 Answer: 5 and 6 If you have any doubt or if you have more problems my e-mail is: mthman@gmail.com