SOLUTION: Find the consecutive numbers such that one- third the greater number exceeds one- fifth of the lesser number by 7.

Question 625360: Find the consecutive numbers such that one- third the greater number exceeds one- fifth of the lesser number by 7.

Answer by reynard2007(52) (Show Source): You can put this solution on YOUR website!

Let (x+1) and (x) be the consecutive numbers. We get one-thir of the bigger number by addin 7 to one-fifth of the smaller.

To get rid of the fractions, we multiply both sides of the equation by their LCD, 15. We get:

The consecutive numbers are 50 and 51. Just check the answer aainst the problem and tell me what happens. :D
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