SOLUTION: one positive integer is 2 less than twice another. the sum of their squares is 193. what are the integers?
Algebra.Com
Question 622459: one positive integer is 2 less than twice another. the sum of their squares is 193. what are the integers?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let 
represent "another number", then the first number must be 
The sum of the squares is 193 means:
^2\ =\ 193)
Expand the squared binomial, collect like terms in the LHS, put the equation in standard form, and then solve the quadratic equation for
Hint: The quadratic factors over the rational numbers, but it may be easier just to use the quadratic formula. Since you now know the quadratic factors over the rationals (I did it, so I know) you can be assured that the discriminant is a perfect square.
John
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
One positive integer is 2 less than twice another. The sum of their squares is 1009.... (answered by Alan3354)
One positive integer is 2 less than twice another. The sum of their squares is 337. Find... (answered by josgarithmetic)
One positive integer is 5 less than twice another. The sum of their squares is 325. Find... (answered by solver91311)
one positive integer is 1 less than twice another. the sum of their squares is 218. find... (answered by Fombitz)
One positive integer is
3 less than twice another. The sum of their squares is
698. (answered by Alan3354)
One positive integer is 1 less than twice another. The sum of their squares is 34. Find... (answered by Boreal)
One positive integer is 6 less than twice another. The sum of their squares is 296. Find... (answered by ikleyn)
One positive integer is 3 less than twice another. The sum of their squares is... (answered by CubeyThePenguin)
one positive integer is 1 less then twice another. the sum of their squares is 673. find... (answered by Math_prodigy)
