# SOLUTION: 9 divided by the difference of a number and 1 minus 8 divided by a number plus 1, equals 9 times the reciprocal of the difference of the number squared 1.

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 Question 621492: 9 divided by the difference of a number and 1 minus 8 divided by a number plus 1, equals 9 times the reciprocal of the difference of the number squared 1.Answer by ankor@dixie-net.com(15639)   (Show Source): You can put this solution on YOUR website!Let n = "a number" : Assume the statement is: "9 divided by the difference of a number and 1 minus 8 divided by a number plus 1, equals 9 times the reciprocal of the difference of the number squared and 1." : - = 9() we can factor the 3rd denominator, as the "difference of squares" - = 9() : multiply by (x+1)(x-1), results gets rid of the denominators and we have 9(n+1) - 8(n-1) = 9 9n + 9 - 8n + 8 = 9 9n - 8n = 9 - 17 n = -8 : : Check this replace n with -8 - = 9() - = 9() + = -1 + =