SOLUTION: 9 divided by the difference of a number and 1 minus 8 divided by a number plus 1, equals 9 times the reciprocal of the difference of the number squared 1.

Question 621492: 9 divided by the difference of a number and 1 minus 8 divided by a number plus 1, equals 9 times the reciprocal of the difference of the number squared 1.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Let n = "a number"
:
Assume the statement is:
"9 divided by the difference of a number and 1 minus 8 divided by a number plus 1, equals 9 times the reciprocal of the difference of the number squared and 1."
:
- = 9()
we can factor the 3rd denominator, as the "difference of squares"
- = 9()
:
multiply by (x+1)(x-1), results gets rid of the denominators and we have
9(n+1) - 8(n-1) = 9
9n + 9 - 8n + 8 = 9
9n - 8n = 9 - 17
n = -8
:
:
Check this replace n with -8
- = 9()
- = 9()
+ =
-1 + =
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